Course Content
Chapter 01 – Operations on Sets
The set operations are performed on two or more sets to obtain a combination of elements as per the operation performed on them. In a set theory, there are three major types of operations performed on sets, such as: Union of sets (∪) The intersection of sets (∩) Difference of sets ( – ) In this lesson we will discuss these operations along with their Venn diagram and will learn to verify the following laws: Commutative, Associative, Distributive, and De-Morgans' law.
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Chapter 02 – Real Numbers
All real numbers follow three main rules: they can be measured, valued, and manipulated. Learn about various types of real numbers, like whole numbers, rational numbers, and irrational numbers, and explore their properties. In this chapter, we will learn about Squares and cubes of real numbers and find their roots.
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Chapter 03 – Number System
The number system or the numeral system is the system of naming or representing numbers. There are different types of number systems in Mathematics like decimal number system, binary number system, octal number system, and hexadecimal number system. In this chapter, we will learn different types and conversion procedures with many number systems.
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Chapter 04 – Financial Arithmetic
Financial mathematics describes the application of mathematics and mathematical modeling to solve financial problems. In this chapter, we will learn about partnership, banking, conversion of currencies, profit/markup, percentage, and income tax.
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Chapter 05 – Polynomials
In algebra, a polynomial equation contains coefficients, exponents, and variables. Learn about forming polynomial equations. In this chapter, we will study the definition and the three restrictions of polynomials, we'll tackle polynomial equations and learn to perform operations on polynomials, and learn to avoid common mistakes.
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Chapter 06 – Factorization, Simultaneous Equations
In algebra, factoring is a technique to simplify an expression by reversing the multiplication process. Simultaneous Equations are a set of two or more algebraic equations that share variables and are solved simultaneously. In this chapter, we will learn about factoring by grouping, review the three steps, explore splitting the middle term, and work examples to practice verification and what simultaneous equations are with examples. Find out how to solve the equations using the methods of elimination, graphing, and substitution.
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Chapter 07 – Fundamentals of Geometry
Geometry is the study of different types of shapes, figures, and sizes. It is important to know and understand some basic concepts. We will learn about some of the most fundamental concepts in geometry, including lines, polygons, and circles.
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Chapter 08 – Practical Geometry
Geometric construction offers the ability to create accurate drawings and models without the use of numbers. In this chapter, we will discover the methods and tools that will aid in solving math problems as well as constructing quadrilaterals and right-angled triangles.
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Chapter 09 – Areas and Volumes
The volume and surface area of a sphere can be calculated when the sphere's radius is given. In this chapter, we will learn about the shape sphere and its radius, and understand how to calculate the volume and surface area of a sphere through some practice problems. Also, we will learn to use and apply Pythagoras' theorem and Herons' formula.
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Chapter 10 – Demonstrative Geometry
Demonstrative geometry is a branch of mathematics that is used to demonstrate the truth of mathematical statements concerning geometric figures. In this chapter, we will learn about theorems on geometry that are proved through logical reasoning.
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Chapter 11 – Trigonometry
Sine and cosine are basic trigonometric functions used to solve the angles and sides of triangles. In this chapter, we will review trigonometry concepts and learn about the mnemonic used for sine, cosine, and tangent functions.
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Chapter 12 – Information Handling
Frequency distribution, in statistics, is a graph or data set organized to show the frequency of occurrence of each possible outcome of a repeatable event observed many times. Measures of central tendency describe how data sets are clustered in a central value. In this chapter, we will learn to construct the frequency distribution table, and learn more about three measures of central tendency, its importance, and various examples.
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Mathematics – VIII
About Lesson

Binary Subtraction

Binary subtraction is the process of subtracting binary numbers. Binary numbers include only 0 and 1. The process of binary subtraction is the same as the arithmetic operation of subtraction that we do with numbers. Since only 0 and 1 are involved here, we may sometimes need to subtract 0 from 1. In such cases, we use the concept of borrowing as we do in an arithmetic subtraction. A binary number is expressed with a base-2. 

What is Binary Subtraction?

Can you subtract binary numbers? The answer is yes. Subtraction of binary numbers is an arithmetic operation similar to the subtraction of decimal numbers or base 10 numbers. For example, 1 + 1 + 1 = 3 in base 10 and 1 + 1 + 1 = 11 in binary number system. When you add and subtract binary numbers, you will need to be careful when borrowing as these will take place more often.

When you subtract several columns of binary digits, you must take into account the borrowing. When 1 is to be subtracted from 0, the result is 1 where 1 is borrowed from the next highest order bit or digit.

Binary Subtraction Rules

Rules and tricks: Binary subtraction is much easier than the decimal subtraction when you remember the following rules:

Arithmetic Operations of Binary Numbers - GeeksforGeeks

Now, look at the example of the binary subtraction: 101 from 1010

How To Do Binary Subtraction?

Decimal or base-10 numbers can be expressed as binary numbers. Binary numbers are used in computers to represent data since they understand only binary digits, 0 and 1. Let us understand how to subtract binary numbers with the example shown below.

Procedure to do Binary Subtraction:

1010

(-) 101

Step 1: First consider the 1’s column, and subtract the one’s column,( 0 – 1 ) and it gives the result 1 as per the condition of binary subtraction with a borrow of 1 from the 10’s place.

Step 2: After borrowing 1 from the 10’s column, the value 1 in the 10’s column is changed into the value 0

1 Borrow

1 0 1 0

(-) 1 0 1

——————

1

Step 3: So, subtract the value in the 10’s place, ( 0 – 0 ) = 0.

1 Borrow

1 0 1 0

(-) 1 0 1

——————

0 1

Step 4: Now subtract the values in 100’s place. Borrow 1 from the 1000’s place ( 0 – 1 ) = 1.

1 1 Borrow

1 0 1 0

(-) 1 0 1

——————

0 1 0 1

So, the resultant of the subtraction operation is 0101.

When you cross-check the binary subtraction resultant value with the decimal value, the resultant value should be the same.

The binary value 1010 is equal to the decimal value 10, and 101 is equivalent to 5

So, 10 – 5 = 5

Therefore, the decimal number 5 is equal to the binary number 0101.

Binary Subtraction Using 1’s Complement

  • The number 0 represents the positive sign
  • The number 1 represents the negative sign
Procedures for Binary Subtraction by 1’s Complement
  • Write the 1’s complement of the subtrahend
  • Then add the 1’s complement subtrahend with the minuend
  • If the result has a carryover, then add that carry over in the least significant bit
  • If there is no carryover, then take the 1’s complement of the resultant, and it is negative.

Example: Subtract 1000102 from 1101012 using 1’s complement method of binary subtraction.

Solution:

Step 1: Find the 1’s complement of the subtrahend, which is 1000102. The 1’s complement is 0111012.

Step 2: Add it with the minuend.

Step 3:

          0 1 1 1 0 1 
       + 1 1 0 1 0 1 
     ——————-
       1 0 1 0 0 1 0
    ——————–

Step 4: Here we get the last left-most digit 1 as a carryover. Now, we add it with the result obtained in step 3.

Step 5: Therefore, we get,

             0 1 0 0 1 0 
                         + 1
            —————-
             0 1 0 0 1 1
            —————-

The decimal equivalent of  is 53 and the decimal equivalent of  is 34. Therefore the result is 19. The binary equivalent of 19 is 100112.

Example: (110101)2 – (100101)2

Solution:

(1 1 0 1 0 1)= 5310

(1 0 0 1 0 1)= 3710 – subtrahend

Now take the 1’s complement of the subtrahend and add with minuend.

1 carry

1 1 0 1 0 1

(+) 0 1 1 0 1 0

——————

0 0 1 1 1 1

1 carry

——————

0 1 0 0 0 0

Therefore, the solution is 010000.

Example: (101011)2 – (111001)2

Solution:

Take 1’s complement of the subtrahend

1 1 1

1 0 1 0 1 1

(+) 0 0 0 1 1 0 (1’s complement)

——————

1 1 0 0 0 1

Now take the 1’s complement of the resultant since it does not carry 1

The resultant becomes 0 0 1 1 1 0

Now, add the negative sign to the resultant value

Therefore the solution is – (001110)2.

Exercise Files
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